# 使用for循环即可! 需要考虑末位
class Solution:
    def areNumbersAscending(self, s: str) -> bool:
        pre=0
        num=0
        for i in s:
            if '0'<=i<='9':
                num=num*10+ord(i)-ord('0')
            else:
                if num>=1:
                    if pre>=num:return False
                    pre=num
                num=0
        # 需要考虑到末位
        if num and pre>=num:return False
        return True

# 使用while遍历即可
class Solution:
    def areNumbersAscending(self, s: str) -> bool:
        pre=0
        n=len(s)
        i=0
        num=0
        while i<n:
            if s[i].isdigit():
                while i<n and s[i].isdigit():
                    num=num*10+ord(s[i])-ord('0')
                    i+=1
                if not pre:
                    pre=num
                elif pre>=num:return False
                else:pre=num
                print(num)
                num=0
            i+=1
        return True